Monday, July 14, 2014

Finding prime numbers | LeetCode



Output all prime numbers up to a specified integer n.
void prime_sieve(int n, bool prime[]) {
  prime[0] = false;
  prime[1] = false;
  int i;
  for (i = 2; i <= n; i++)
    prime[i] = true;
  int limit = sqrt(n);
  for (i = 2; i <= limit; i++) {
    if (prime[i]) {
      for (int j = i * i; j <= n; j += i)
        prime[j] = false;
    }
  }
}
Read full article from Finding prime numbers | LeetCode

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